Answer: A voltmeter is connected in parallel across the two points where the potential difference is to be measured. This is because a voltmeter has very high resistance, ensuring it does not draw significant current and measures the accurate voltage drop.
Answer: We know that charge on one electron ($e$) = $1.6 \times 10^-19 \text C$. Let $n$ be the number of electrons constituting a total charge of $1 \text C$. Total Charge ($Q$) = $n \times e$ $$1 \text C = n \times 1.6 \times 10^-19 \text C$$ $$n = \frac11.6 \times 10^-19$$ $$n = 6.25 \times 10^18$$ Therefore, approximately $6.25 \times 10^18$ electrons constitute one coulomb of charge.
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Electricity is a fundamental part of our daily lives. It powers our homes, schools, and industries, and is a crucial aspect of modern technology. In Class 10, students learn about the basics of electricity, including its definition, types, and applications.
Mastering Physics: Comprehensive Guide to Electricity NCERT Solutions Class 10 Answer: A voltmeter is connected in parallel across
We know the relation: $V = \fracWQ$ or Work Done ($W$) = $V \times Q$ $$W = 6 \text V \times 1 \text C = 6 \text J$$ Therefore, of energy is given to each coulomb of charge.
Let $n$ be the number of resistors connected in parallel. Formula for parallel resistance: $\frac1R_p = \fracnR$ (where $R$ is the resistance of one resistor). $$\frac144 = \fracn176$$ $$n = \frac17644 = 4$$ are required. Let $n$ be the number of electrons constituting
Total Resistance = $\frac242 = 12 \ \Omega$ $$I = \frac22012 = 18.33 \text A$$
Total Current ($I$): $$I = \fracVR_p = \frac22031.25 = 7.04 \text A$$
Answer: When resistors are connected in parallel, the equivalent resistance ($R_p$) is given by: $$\frac1R_p = \frac1R_1 + \frac1R_2 + \dots$$