The total applied force $P$ is the sum of the forces resisted by steel ($P_st$) and aluminum ($P_al$). $$P_st + P_al = P$$ $$P_st + P_al = 150,000 \text N$$
$$\delta = \frac50,000 \text N \times 2000 \text mm314.16 \text mm^2 \times 200,000 \text N/mm^2$$
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And always, always draw the free-body diagram first.
Substitute $P_st$ into the equilibrium equation: $$1.43 P_al + P_al = 150,000$$ $$2.43 P_al = 150,000$$ $$P_al = 61,728 \text N$$ $$P_st = 150,000 - 61,728 = 88,272 \text N$$ The total applied force $P$ is the sum
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Solutions converting horsepower or kilowatts into mechanical torque inputs for drive shafts. 4. Shear Force and Bending Moment in Beams Substitute $P_st$ into the equilibrium equation: $$1
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